Question 937818
{{{lim(x->0, ((x-2)^3 + 8)/x) }}}

so apply the l hospital rule and differentiate now the question can be written as 

 {{{dy/dx =3((x-2)^2)/1}}}=> if {{{x->0}}} we have  {{{dy/dx =3(0-2)^2}}} => {{{dy/dx =3*4=12}}}


{{{lim(x->0, ((x-2)^3 + 8)/x)=12 }}}