Question 937753
x = time downwind
y = time upwind
x + y = 5.25
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z = 1/2 the total distance of the training ride
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s = d/t
t = d/s
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time downwind:
x = z/24
z = 24x
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time upwind:
y = z/18
z = 18y
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equate z's:
24x = 18y
24x - 18y = 0
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linear system:
x + y = 5.25
24x - 18y = 0
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put the system of linear equations into standard form
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x + y = 5.25
24x - 18y = 0
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solution:
x = time downwind = 2.25
y = time upwind = 3
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answer:
he will ride 2.25 hours on his out-bound leg ...
z = 24x
z = 24*2.25
z = 54
he will ride 54 miles downwind, at which point he must turn around and head back home
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