Question 937739
A freight train passes through a 750 metre long tunnel at 50km/hr. The back of the train exits the tunnel 1.5 min after the front of the train enters it. What is the length of the train, in metres?
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distance front of train goes in 1.5 min::
50(km/hr) = 50[1000 m/60 min) = (50000/60) = 833.33 meters/min
1.5*833.33 = 1250 meters in 1.5 minutes
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Let train length be "x meters"::
Distance traveled to enter and clear the tunnel in 1.5 min::
750 + x meters = 1250 meters
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Ans:: x = 500 meters (length of the train
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Cheers,
Stan H.