Question 79576
Factor by grouping:
{{{(xy+3x+2y+6)/(xy+3x+5y+15)}}} Group as shown below:
{{{((xy+3x)+(2y+6))/((xy+3x)+(5y+15))}}} Factor as shown below:
{{{(x(y+3)+2(y+3))/(x(y+3)+5(y+3))}}} Factor the (y+3)'s in both the numerator and the denominator.
{{{(cross((y+3))(x+2))/(cross((y+3))(x+5))}}} Cancel the indicated terms.
{{{(x+2)/(x+5)}}}...and there you have it!