Question 937642
Ramon has traveled 126 mi from start
Ashaki has traveled 62 mi from start 
So, they are {{{ 126 - 62 = 64 }}} mi apart
and Ramon is ahead
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Let {{{ t }}} = time in hrs for Ashaki to catch him.
She is {{{ 64 }}} mi behind, but she is traveling 
faster, so it is possible to catch Ramon.
Let {{{ d }}} = the distance in miles  that Ashaki 
has to travel to catch Ramon.
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Ramon's equation:
(1) {{{ d - 64 = 50t }}}
Ashaki's equation:
(2) {{{ d = 58t }}}
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Substitute (2) into (1)
(1) {{{ 58t - 64 = 50t }}}
(1) {{{ 8t = 64 }}}
(1) {{{ t = 8 }}} 
Ashaki catches up with Ramon in 8 hrs
check:
(2) {{{ d = 58t }}}
(2) {{{ d = 58*8 }}}
(2) {{{ d = 464 }}} mi
and
(1) {{{ d - 64 = 50t }}}
(1) {{{ d - 64 = 50*8 }}}
(1) {{{ d = 400 + 64 }}}
(1) {{{ d = 464 }}}
OK