Question 79558
ln(x+1)= ln(3x+1)-ln x
ln(x+1) = ln[(3x+1)/x]
Since the ln's are equal, the anti-ln's are equal:
x+1 = (3x+1)/x
x^2+x = 3x+1
x^2-2x-1=0
x=[2+-sqrt4-4*-1]/2
x=[2+-sqrt(8)]/2
x=[1+-sqrt2]
Positive answer:
x=1+sqrt2
x=2.1414....
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Cheers,
Stan H.