Question 937560
A. 

points are: ({{{0}}},{{{0}}}) ({{{15}}},{{{5}}})

The slope of a line is a rate of change.

{{{m=(y[2]-y[1])/(x[2]-x[1])}}}

{{{m=(5-0)/(15-0)}}}

{{{m=5/15}}}

{{{m=1/3}}}

B. What is the y-intercept of {{{y = 2/sv + 2}}}

the y-intercept is a point where x coordinate is zero: ({{{0}}},{{{b}}})

recall the slope-intercept form of linear equation {{{y=mx+b}}} where {{{m=slope}}} and {{{b=y-intercept}}}

compare it to {{{y = 2/sv + 2}}} and you see that y-intercept is {{{b=2}}} or at point ({{{0}}},{{{2}}})


C. Find the equation of the line.
  
points are: ({{{0}}},{{{1}}}) ({{{-3/2}}},{{{0}}})

{{{m=(y[2]-y[1])/(x[2]-x[1])}}}

{{{m=(0-1)/(-3/2-0)}}}

{{{m=-1/(-3/2)}}}

{{{m=2/3}}}


{{{y=mx+(y[1]-mx[1])}}} plug in ({{{0}}},{{{1}}}) and {{{m=2/3}}}

{{{y=(2/3)x+(1-(2/3)*0))}}}


{{{y=(2/3)x+1}}}



D. 	

linear equation: {{{y=mx+b}}}

if a city had population {{{67255}}} on January {{{1}}}, {{{2000}}} means the constant value or {{{b= 67255}}}

and if its population has been increasing by {{{2935}}} people each year since then:means {{{m=2935 }}} is rate of change or slope and {{{x=t}}} represents years 

so,a linear model for the population {{{P}}}, where {{{t}}} is in years after {{{2000}}}, is:
{{{P(T)=2935*t+67255}}}

answer: d. P(t) = 67255 + 3955t-> I believe this is mistake, should be 2935t



E. Write an equation of the line that has a slope of {{{-(2/3)}}} and a {{{y- intercept}}} of {{{-2}}}?

linear equation {{{y=mx+b}}} where {{{m=slope}}} and {{{b=y-intercept}}}

if {{{m=-(2/3)}}} and {{{b=-2}}}, we have

{{{y=-(2/3)x-2}}}