Question 937559
They would still be variables in a formula.

radius, r.
height, h.
circumference, {{{2pi*r}}}.



{{{c=2pi*r}}} for circumference.
{{{c/(2pi)=r}}}
v for volume,
{{{v=h*pi*r^2}}}
You are given v=1.


{{{h*pi*r^2=1}}}
{{{h*pi*(c/(2pi))^2=1}}}
{{{(1/4)h*pi*(c^2/pi^2)=1}}}
{{{highlight((hc^2)/(4pi)=1)}}}, allowing inverse variation between measurements for c and h, circumference and height.