Question 937255
Solve the following for 0 < x < 2pi
(sin x + cos x)^2 = 1
(sinx+cosx)^2=sin^2(x)+2sinxcosx+cos^2(x)=1+sin(2x)
1+sin(2x)=1
sin2x=0
2x=0
x=0
no solution: x not in given domain