Question 937175
let 3 consecutive even integers be x,x+2,x+4

 3 times the first equal to the sum of the other 2 consecutive even integers
         3*x= x+2+x+4
       3x= 2x+6
         3x-2x= 6
         x=6
    x+2 = 6+2 = 8
     x+4 = 6+4 = 10
 3 consecutive integers (x,x+2. x+4) are  6,8,10