Question 937095
x = speed of faster car
y = speed of slower car
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x = y + 10
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s = d/t
s = 300/3
s = 100
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speed of cars relative to each other:
s = x + y
s = y + 10 + y
s = 2y + 10
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equate s's:
2y + 10 = 100
2y = 90
y = 45
x = 55
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answer:
x = speed of faster car = 55 mph
y = speed of slower car = 45 mph
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