Question 937073
<pre>

No! Because 

{{{(4x-6)^2=(4x-6)(4x-6)=16x^2-24x-24x+36 =16x^2-48x+36}}} which is not {{{16x^2-36}}}

The correct way to factor {{{16x^2-36}}} is

First take out the GCF which is 4, getting {{{4(4x^2-9)}}} then
that is the difference of squares which factors as the difference and
sum of the square roots, and the result is {{{4(2x-3)2x+3)}}}.

Edwin</pre>