Question 936967
{{{y=a(x-(-3))^2+16}}}
{{{y=a(x+3)^2+16}}}
When {{{x=0}}},
{{{y=a(0+3)^2+16=-20}}}
{{{9a+16=-20}}}
{{{9a=-36}}}
{{{a=-4}}}
So then,
{{{y=-4(x+3)^2+16}}}
{{{0=-4(x+3)^2+16}}}
{{{4(x+3)^2=16}}}
{{{(x+3)^2=4}}}
{{{x+3= 0 +- 2}}}
{{{x=-3 +- 2}}}
{{{x=-1}}} and {{{x=-5}}}
Now use the x values to generate y values in {{{y=-4(x+3)^2+16}}} and your answer is complete.