Question 936950
For the number AB
Equation 1: {{{B = 2A}}}
Equation 2: {{{2*(10A + B) = 10B + A + 6}}}
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Note that equation 1 is already solved for B
Plug 2A into equation 2 for B
Equation 2: {{{2*(10A + B) = 10B + A + 6}}}
{{{2*(10A + (2A)) = 10*(2A) + A + 6}}}
Simplify
{{{20A + 4A = 20A + A + 6}}}
Combine like terms.
{{{24A = 21A + 6}}}
Subtract 21A from both sides.
{{{3A = 6}}}
Divide both sides by 2.
{{{highlight(A = 2)}}}
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Now plug 2 into equation 1 for A
Equation 1: {{{B = 2A}}}
{{{B = 2*(2)}}}
{{{highlight_green(B = 4)}}}

The number is 24