Question 936884
 let x,x+1,x+2,x+4 be the 4 consecutive whole numbers
 sum   = x+(x+1)+(x+2)+(x+3)
      = x+x+1+x+2+x+3
     = 4x+6
  4x+6 = 2014
   4x= 2014-6
 4x= 2008
  divide with 4 on both sides
 {{{ 4x/4  = 2008/4}}}
   {{{ x= 502}}}
 so   the four numbers are as follows 
         x= 502
         x+1 = 502+1 = 503
       x+2 = 504
        x+3 = 505
numbers are  = 502,503,504,505
           sum of digits of all numbers  = 5+0+2+5+0+3+5+0+4+5+0+5
                                           =34
 Result : 34