Question 936890
{{{a^0 = 1}}}
{{{( x^m )( x^n ) = x^( m + n )}}}
{{{x^m/x^n=x^(m-n)}}}
{{{(a^p)^q = a^(p*q)}}} ***
{{{(xy)^n = x^n*y^n}}}
x^(1/n) = {{{root(n,x)}}}   
x^(m/n) = {{{root(n,x^m)}}}***
.........
(4^1x^-2^1y^1/3)^3/2 = 4^(3/2)x^(-3) - 2^(3/2)y^(1/2) = 8/x^3 - 2√2√y
........
4^(3/2) = {{{root(2,4^3)}}} = 8
2^(3/2) = {{{root(2,2^3) = sqrt(8)}}} = 2√2