Question 936879
The general equation for a circle centered at (h,k) with radius R is,
{{{(x-h)^2+(y-k)^2=R^2}}}
1. {{{(x-1)^2+(y-4)^2=25}}}
Now do the same for 2.
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To get to the general equation, complete the square in x and y,
{{{ x^2+4x+y^2-6y=12}}}
{{{ (x^2+4x+4)+(y^2-6y+9)=12+4+9}}}
{{{(x+2)^2+(y-3)^2=25}}}
({{{-2}}},{{{3}}}), {{{R=5}}}
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{{{x^2-8x+y^2+2y=16}}}
{{{(x^2-8x+16)+(y^2+2y+1)=16+16+1}}}
{{{(x-4)^2+(y+1)^2=33}}}
({{{4}}},{{{-1}}}), {{{R=sqrt(33)}}}