Question 936857
3x-5 must be non-negative.


{{{f(x)=sqrt(3x-5)}}}


{{{3x-5>=0}}}
{{{3x>=5}}}
{{{x>=5/3}}}


f(x) never reaches a limit; it continues to increase but the increase in value gets smaller.  No vertical asymptote.  


DOMAIN:  Real numbers such that {{{x>=5/3}}}.
RANGE:  Real numbers {{{f(x)>=0}}} or all non-negative real numbers.


{{{graph(250,250,-2,10,-2,10,sqrt(3x-5))}}}
The graph curve is supposed to touch the x-axis.