Question 936711
{{{3x-y=6}}}
{{{y=3x-6}}}
.
.
{{{xy=24}}}
{{{x(3x-6)=24}}}
{{{x(x-2)=8}}}
{{{x^2-2x=8}}}
{{{x^2-2x-8=0}}}
{{{(x-4)(x+2)=0}}}
Two solutions:
{{{x-4=0}}}
{{{x[1]=4}}}
Then,
{{{4y=24}}}
{{{y[1]=6}}}
and
{{{x+2=0}}}
{{{x[2]=-2}}}
Then,
{{{-2y=24}}}
{{{y[2]=-12}}}
So then,
{{{x[1]+y[1]+x[2]+y[2]=4+6-2-12=highlight(-4)}}}