Question 933612
For the cone,
{{{V[k1]=(pi/3)R^2*H}}}
{{{V[k2]=(pi/3)(3R)^2*(H/2)=(9/2)(pi/3)R^2*H=((3pi)/2)R^2*H}}}
{{{n[k]=((3pi)/2)/(pi/3)}}}
{{{n[k]=9/2}}}
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For the cylinder,
{{{V[c1]=pi*R^2*H}}}
{{{V[c2]=pi*R^2*(2H)}}}
{{{n[c]=V[c2]/V[c1]=2}}}
Cone has greatest change in volume.