<PRE><B>Question 936693</B>
What is the formula for the nth term of a geometric sequence with a4 = 16 and r = `1/2`?
a(4) = a*(1/2)^3 = 16
a = 16/(1/8)
a = 128
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a(n) = 128*(1/2)^(n-1)
Cheers,
Stan H.
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C)`a_(n)=128(1/2)^(n-1)` 

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