Question 936694
What is the solution of 5 = 17x^2 - 200x ?
A. 1 real number
B. 2 complex numbers that are conjugates
C. 2 real unequal numbers
D. 0
E. none of these

Solution:
Express the equation in the form {{{ax^2 + bx + c = 0}}}, then identify the values of a, b, and c.
{{{17x^2 - 200x - 5 = 0}}}
a = 17, b = -200, and c = -5
The discriminant is {{{b^2 - 4ac}}} = 40340 > 0 [positive number]
Therefore, the answer is C. 2 real unequal numbers