Question 79420
Factor x^12-x^4-x^3+1
{{{(x^12-x^4)+(-x^3+1)}}}  factor by grouping
{{{x^4(x^3-1)-1(x^3-1)}}}
{{{(x^4-1)(x^3-1)}}}
The difference of squares a^2-b^2=(a+b)(a-b)
The difference of cubes a^3-b^3=(a-b)(a^2+ab+b^2)
{{{(x^2+1)(x^2-1)(x-1)(x^2+x+1)}}}
{{{(x^2+1)(x+1)(x-1)(x-1)(x^2+x+1)}}}
This can be in a different order or like this:
{{{(x+1)(x-1)^2(x^2+1)(x^2+x+1)}}}
Happy Calculating!!!!