Question 936492
Let's look at the distance once around. 
For the inside radius, x, the circumference would be,
{{{C[x]=2pi*x}}}
For the next lane at radius, x+2.5, the circumference would be,
{{{C=2pi*(x+2.5)=2pix+5pi=C[x]+5pi}}}
So the next lane would run an additional 5 pi to get to the same point. 
So if you stagger the inside runner back {{{5pi}}} feet, they would run the same distance. 
So every lane would be staggered {{{5pi}}} feet from the lanes around it, clockwise going inwards, counterclockwise going outwards (assuming the race is counterclockwise).