Question 79394
:
Assume you mean:
:
{{{((7x+1))/((x^2-9))}}} - {{{5/((x-3))}}}
:
You should recognize that (x^2-9) is the difference of squares and can be factored
{{{((7x+1))/((x+3)(x-3))}}} - {{{5/((x-3))}}}
:
The common denominator would be (x-3)(x+3) so you would have:
{{{((7x+1)-5(x+3))/((x+3)(x-3))}}} = {{{(7x + 1 - 5x - 15)/((x+3)(x-3))}}} = {{{(2x - 14)/((x+3)(x-3))}}} or {{{(2x - 14)/((x^2 - 9))}}}