Question 936448
<pre>
a<sub>15</sub> = 129, a<sub>8</sub>=22(a1) 

<u>   </u>,<u>   </u>,<u>   </u>,<u>   </u>,<u>   </u>,<u>   </u>,<u>   </u>,<u>  22</u>,<u>   </u>,<u>   </u>,<u>   </u>,<u>   </u>,<u>   </u>,<u>   </u>,<u>129</u> 

Let d be the common difference.  Then since 129 is the 7th term after
22, one would have to add the common difference d seven times to get 129,
ao

22+7d=129
   7d=107
    d={{{107/7}}}
    d={{{15&2/7}}}

Now since 22 is the 7th term before the first term we would have to subtract
this common difference d seven times to get the first term,  

so the first term = {{{22-7(107/7)=22-107=-85}}} 

First term = -85 and common difference = {{{15&2/7}}}.

FYI, the whole sequence is:

<u>{{{-85}}}</u>,<u>{{{-69&5/7}}}</u>,<u>{{{-54&3/7}}}</u>,<u>{{{-39&1/7}}}</u>,<u>{{{-23&6/7}}}</u>,<u>{{{-8&4/7   }}}</u>,<u>{{{6&5/7}}}</u>,<u>{{{ 22}}}</u>,<u>{{{37&2/7}}}</u>,<u>{{{52&4/7}}}</u>,<u>{{{67&6/7}}}</u>,<u>{{{83&1/7   }}}</u>,<u>{{{98&3/7}}}</u>,<u>{{{113&5/7}}}</u>,<u>{{{129}}}</u>

Edwin</pre>