Question 936400
let x-1,x,x+1 be the three consecutive whole numbers
 their sum   =(x-1)+x+((x+1)
              =x-1+x+x+1
              =3x
but the sum is 2013
   3x= 2013
   divide with on both sides
 {{{ 3x/3  = 2013/3}}}
 {{{ x= 671}}}
     x=671
   x-1  =671-1 =670
   x+1 = 671+1 =672
  so the three consecutive whole numbers are 670,671,672