Question 936257
{{{3*log((x-2))=log((2x))-3}}}


{{{log(((x-2)^3))-log((2x))=-3}}}


{{{log(((2x)/(x-2)^3))=3}}}


You must have a base, arbitrarily chose here as b; and you can express
{{{b^3=(2x)/(x-2)^3}}}