Question 936299
Solve for y in terms of x, and use the separate inequalities and their related lines.


{{{y<3(abs(x+5))+2+3}}}
{{{y<3*abs(x+5)+5}}}

Critical value is x=-5.



{{{x+5>0}}}
-
{{{y<3(x+5)+5}}}
{{{y<3x+15+5}}}
{{{y<3x+20}}}



{{{x+5<0}}}
-
{{{y<3(-x-5)+5}}}
{{{y<-3x-15+5}}}
{{{y<-3x-10}}}


What happens AT x=-5?
{{{y<abs(3(-5)+15)+5?}}}
{{{y<abs(-15+15)+5}}}
{{{y<5}}}



SUMMARY
{{{y<3x+20}}}_________{{{x>-5}}}
{{{y<-3x-10}}}________{{{x<-5}}}


The equality <i>would</i> be:
{{{graph(300,300,-10,3,-3,10,y=3*abs(x+5)+5)}}}


The inequality is, keeping all graph regions in the same positions,
{{{graph(300,300,-10,3,-3,10,y-3<abs(3x+15)+2)}}}