Question 936276
what is an equation of a line that is perpendicular to y=3/5x-2 and passed through point(5,-7)
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The given line has slope = 3/5
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A perpendicular line must have slope -5/3
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Form::
y = mx + b
Substitute for x,y,m and solve for "b":
-7 = (-5/3)5 + b
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-21/3 = -25/3 + b
b = -46/3
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Ans: y = (-5/3)x - (46/3)
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Cheers,
Stan H.
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