<PRE><B>Question 936226</B>
log(2) (x+5) - log(2) (2x)=8  Note: 2^8 = 256
(x+5)/2x = 256
x+5 = 512x
5/511 = x
.......
*[tex \large\ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]***
*[tex \large\ \ nlog_bx = log_b(x^n) ]
*[tex \large\ \ log_bx + log_by = log_b(xy) ]
*[tex \large\ \ log_bx - log_by = log_b(x/y) ]***
*[tex \large\ \ log_b1 = 0]
*[tex \large\ \ log_bb = 1]
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