<PRE><B>Question 936092</B>
Solve the logarithmic equation: log2 4+log2 x=6
I got x=2, is this correct?
&lt;pre&gt;&lt;font face = &quot;Tohoma&quot; size = 4 color = &quot;indigo&quot;&gt;&lt;b&gt;log&lt;sub&gt;2&lt;/sub&gt; 4 + log&lt;sub&gt;2&lt;/sub&gt; x = 6
log&lt;sub&gt;2&lt;/sub&gt; 4x = 6
4x = 2&lt;sup&gt;6&lt;/sup&gt;
4x = 64
{{{x = 64/4}}}, or {{{highlight_green(16)}}}
OR
log&lt;sub&gt;2&lt;/sub&gt; 4 + log&lt;sub&gt;2&lt;/sub&gt; x = 6
log&lt;sub&gt;2&lt;/sub&gt; 2&lt;sup&gt;2&lt;/sup&gt; + log&lt;sub&gt;2&lt;/sub&gt; x = 6
2 + log&lt;sub&gt;2&lt;/sub&gt; x = 6
log&lt;sub&gt;2&lt;/sub&gt; x = 6 - 2
log&lt;sub&gt;2&lt;/sub&gt; x = 4
x = 2&lt;sup&gt;4&lt;/sup&gt;
{{{highlight_green(x =  16)}}}
You can do the check!! 
You should be able to determine if you&#39;re correct, or incorrect, I&#39;m sure!!
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