Question 932162
{{{ 2/y  +5/2 =4 -2/(3y)}}}
 *[invoke explain_simplification "(2/y)  +(5/2) =4 -2/(3y)" ]
from the above 
 we got {{{ (8/3y)- 3/2  =0}}}
          move 3/2 to the right
  {{{ 8/3y  =  3/2}}}
      multiply with 3y on both sides
      {{{  (8/3y ) *3y =  (3/2)*3y}}}
              {{{ 8=  9y/2}}
              {{{ 8*2 =9y}}
          {{{ 16 =9y}}}
                      divide with  9 on both sides
 {{{ 16/9 = 9y/9}}}
      16/9 =  y