Question 935951
The height of 18 year old men are approximately normally distributed with a mean of 68 inches and a standard deviation of 3 inches. What is the probability that the average height of a sample of twenty 18 year olds will be less than 69 inches?
Solution:
The z score for 69 is {{{(69-68)/(3/sqrt(20))}}} = 1.4907
P(Z < 1.4907) = {{{highlight(0.9320)}}}