Question 936010
let age of son be x years
age of man is  7*x years
 after 8 years , son's age will be  x+8 
after 8 years , man's age will be 7x+8
 
In 8 years he will be only three times as old as his son
   hence
       7x+8 = 3*(x+8)
 7x+8 = 3x+3*8
 7x+8 = 3x+24
    move 3x to the left
    7x+8-3x= 24
       7x-3x+8 = 24
       4x+8 =24
 move 8 to the right
     4x = 24-8 
           4x = 16
           divide with 4 on both sides
               {{{ 4x/4  =16/4}}}
               x= 4  
age of son  (x)= 4 years
 age of man  (7x)= 7*4 =28 years
Result : age of man now  = 28 years