Question 79332
let h=hundreds digit, let t=tens digit, let u=ones digit ... h+t+u=9 ... h+t=u-1 ... (100h+10t+u)/9=3u





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from first two equations, u-1+u=9 ... 2u=10 ... u=5 ... t=4-h


using third equation, 100h+10(4-h)+5=3*5*9 ... 100h+40-10h+5=135 ... 90h=90 ... h=1 ... t=3