Question 935979
Simplify the expression (8x^-3 y^6)^-1/3 (2x^-3 y^-1) so that the result is in terms of positive exponents, only.
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(8x^-3 y^6)^-1/3 (2x^-3 y^-1)
Assuming -1/3 is an exponent:
= (2x^-3 y^-1)/(8x^-3 y^6)^(1/3)
= (2x^-3 y^-1)/(2x^-1 y^2)
= y^-1/(x^2y^2)
= 1/(x^2y^3)