<PRE><B>Question 935979</B>
Simplify the expression (8x^-3 y^6)^-1/3 (2x^-3 y^-1) so that the result is in terms of positive exponents, only.
-----------------
(2xy^2)^-1 * (2/x^3y)
-----
= 2/[2xy^2*x^3y)
------
= 1/[x^4y^3]
=========================
Cheers,
Stan H.
-------------------------
 answers
 1) 1/ x^2 y^2
 2) 4/x^2 y^3
 3) x^2 y^3
 4) 1/ 4x^2 y^3</PRE>