Question 935933
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standard ellipse equation:
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(x - h)^2/aa + (y - k)^2/bb = 1
where 0 < b < a
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the foci lie on a horizontal line (both have y=1)
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the foci are 6 units apart ... 5 - (-1) = 6 ...
so the center of the ellipse is 3 units from either focus (c = 3) ...
hence the center of the ellipse is at (2,1)
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h and k are the x,y coordinates of the center:
h = 2
k = 1
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find aa and bb:
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the major axis is 8 units long:
2a = 8
a = 4
aa = 16
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recall the formula: cc = aa - bb
bb = aa - cc
bb = 4*4 - 3*3
bb = 7
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answer:
(x - 2)(x - 2)/16 + (y - 1)(y - 1)/7 = 1
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