Question 934057
{{{2t^2 + 1 = 6t}}}
{{{2t^2 -6t+ 1 = 0}}}
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{{{D=b^2-4ac}}}
{{{D=(-6)^2-4(2)(1)}}}
{{{D=36-8}}}
{{{D=28}}}
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Two real roots.
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{{{graph(300,300,-10,10,-10,10,2x^2-6x+1)}}}