Question 935876
Let the ground distance from one point be x.
Let's name this point Q

We have a triangle ABC

AQ= x
BQ = 100-x
Vertical height BQ = y

the distance from other point will be 100-x

Tan 55 = BT / x

x= BT/tan 55...............................(1)

tan 36 = BT /(100-x)

100-x= BT/tan 36

x= 100-(BT/tan 36)................................(2)

Equate (1) & (2)

BT/tan 55=100-(BT/tan 36)

0.7*BT = 100-1.376 *BT

0.7*BT +1.376 *BT=100

2.076BT =100

BT = 48.16