Question 935837

if the base {{{b}}} and height {{{h}}} of a right triangle are each {{{1in}}}, then the hypotenuse {{{c}}} is:

{{{c^2=b^2+h^2}}}

{{{c^2=(1in)^2+(1in)^2}}} 

{{{c^2=1in^2+1in^2}}} 

{{{c^2=2in^2}}} 

{{{c=sqrt(2in^2)}}} 

{{{c=sqrt(2)in}}}