Question 932749
{{{cos(2x)  =sqrt (3)/2 }}}


{{{arccos(cos(2x))  =arccos(sqrt (3)/2 )}}}


{{{2x=pi/6+2*pi*n}}}

or

{{{2x=(11*pi)/6+2*pi*n}}}


where n is an integer, then...

{{{x=(11*pi)/12+pi*n}}}



{{{x=pi/12+pi*n}}}