Question 935758
Jane averaged her five equally weighted test grades and got 60%. This was wrong because she had entered one grade incorrectly. That incorrect score should have been entered as 80%. If she had used the 80%, her correct average for the five tests would have been 70%. What percent did she incorrectly enter instead of 80%?
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Equations:
4correct scores and 1 error score::
(4c + e)/5 = 60
4c + e = 300
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5 correct scores::
(4c + 80)/5 = 70
4c + 80 = 350
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Solve this system:
4c + e = 300
4c + 80 = 350
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80-e = 50
e = 30
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Answer:: 30%
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Cheers,
Stan H.