Question 79260
find the coordinates of the vertex. and then sketch the graph... 
the problem is: 
y=x^2+6x+12 
You have a quadratic with a=1, b=6
The vertex is at x=-b/2a=-6/2=-3
The y value when x=-3 is (-3)^2+6*(-3)+12 = 3
The vertex is at (-3,3)
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{{{graph(400,300,-10,20,-10,20,x^2+6x+12)}}}
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Cheers,
Stan H.