Question 935673
Use the identity:
{{{ ( sin( 2*theta ) )^2 + ( cos( 2*theta ) )^2 = 1 }}}
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{{{ 1 - ( sin( 2*theta ) )^2 = ( sin( 2*theta ) )^2 + ( cos( 2*theta ) )^2 - sin( 2*theta ) )^2 }}}
{{{ 1 - ( sin( 2*theta ) )^2 = ( cos( 2*theta ) )^2 }}}