Question 935662
How far does Patty get in the {{{ 3 }}} hours
before Toby leaves?
{{{ d[1] = 45*3 }}}
{{{ d[1] = 135 }}} mi
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Start a stopwatch when Toby leaves
Let {{{ t }}} = time in hours on 
stopwatch when they meet
Let {{{ d }}} = distance in miles that
Toby travels until they meet
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Patty's equation:
(1) {{{ 345 -d - 135 = 45t }}}
Toby's equation:
(2) {{{ d = 60t }}}
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Substitute (2) into (1)
(1) {{{ 345 - 60t - 135 = 45t }}}
(1) {{{ 105t = 210 }}}
(1) {{{ t = 2 }}}
They will meet 2 hrs after Toby leaves
3 PM + 2 hrs = 5 PM
is when they meet
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check:
(2) {{{ d = 60t }}}
(2) {{{ d = 60*2 }}}
(2) {{{ d = 120 }}} mi
and
(1) {{{ 345 -d - 135 = 45t }}}
(1) {{{ 345 -120 - 135 = 45*2 }}}
(1) {{{ 90 = 90 }}}
OK