Question 933344
{{{A=x-1}}}
{{{B=x}}}
{{{C=x+1}}}
.
.
.
{{{A+B+C=17}}}
Substituting,
{{{x-1+x+x+1=17}}}
{{{3x=17}}}
{{{x=17/3}}}
{{{A=17/3-3/3=14/3}}}
{{{B=17/3}}}
{{{C=17/3+3/3=20/3}}}