Question 935602
x = distance between the cities (miles)
y = speed of the train (mph)
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s = d/t
t = d/s
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at normal speed:
y = x/2
2y = x
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at reduced speed:
y - 5 = x/(2 + 12/60)
y - 5 = x/2.2
2.2y - 2.2*5 = x
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put the system of linear equations into standard form
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x - 2y = 0
x - 2.2y = -11
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solution:
x = distance between the cities (miles) = 110
y = speed of the train (mph) = 55
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