Question 935621
Solution; 
suppose $ {{{x}}} was lent at {{{6}}}% per annum:
thus,
 
{{{(x*6*5)/100 + ((7000-x)*4*5)/100=1600}}}

{{{3x/10 + (14000-2x)/10=1600}}}

{{{3x/10 + (cross(14000)7000-cross(2)x)/cross(10)5=1600}}}

{{{3x/10+(7000-x)/5=1600}}}

{{{3x+(7000-x)2=1600*10}}}

{{{3x+14000-2x=16000}}}

Therefore 

{{{x=16000-14000}}}

$ {{{x=2000}}}